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Songthumjitti et al. Intell Robot 2023;3(3):306-36  I http://dx.doi.org/10.20517/ir.2023.20  Page 23 of 31


















                                              Figure 28. Fundamental Youla block diagram.



                                                                
                                                          =                                            (20)
                                                           1 −     

               In Equation (18),          can be replaced from Equation (20), and the plant of the system,   , is equal to                ,
                                                                                                         2
               and we will get the result shown in Equation (21).



                                                          2                
                                                  = (1 −            (1 +       ))                      (21)
                                                                    1 +      

               Similarly,           can be expressed with the parameter    as Equation (22).



                                                                        2
                                                        =       (1 +       )(1 −                  )    (22)

               Equation (21) shows that if    is expressed as Equation (23), the sensitivity of the system,   , will be 0. Fur-
               thermore, from Equation (22),           will be just       with the same   ; this means that the effect of the robot
               structure can be completely eliminated.



                                                              1
                                                        =                                              (23)
                                                            2
                                                                  (1 +       )
               But in reality, we know that       has an unstable zero that cause by dead time and also that  1  is unstable itself.
                                                                                             2
               Therefore, the parameter    in Equation (23) is not stable. So,       is divided into two parts, which consist of
               stable zero and unstable zero, as shown in Equation (24), and we only use      0, as shown in Equation (25),
               which is the stable zero part. The result of    is shown in Equation (26).



                                                       =      0 ∗                      .               (24)



                                                                 2   
                                                       0 =                                             (25)
                                                         2            2
                                                           + 2               +      

                                                              1
                                                       =                                               (26)
                                                             2
                                                             0    (1 +       )
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