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Cui et al. Complex Eng Syst 2023;3:3  I http://dx.doi.org/10.20517/ces.2022.57    Page 5 of 15


               where

                        2   2
                      = −2        1 +      2        = −2     1 + 2     2
                            
                      = −2     1    1 + 2     2    2        = 2     1
                          1   −   2   
                      = −2                   = −2 (   1 +    2 )
                      = −2   1    1 − 2   2    2        = 2   1
                                                         1 +     2  2
                      = −[2   1    1 ℎ + 2   2    2 ℎ + 2(   21 +    23 +  )   −         ℎ]
                                                          2
                      = −2 (   21 +    23 )    2
               The following formula can be obtained by Laplace transformation of the above formula
                                                          3    2
                                                   (  )     3    +   2    +   1   +   0
                                                  =
                                                (  )   4   3    2
                                                        4    +   3    +   2    +   1   +   0
                                            
                                                       3    2
                                                 (  )     3    +   2    +   1   +   0                  (8)
                                                  =
                                                       4
                                                            3
                                                                2
                                                 (  )     4    +   3    +   2    +   1   +   0
                                            
                                            
                                                          2
                                               (  )        2    +   1   +   0
                                                 =
                                                                2
                                                       4
                                                            3
                                               (  )     4    +   3    +   2    +   1   +   0
               where
                                        2   2
                            3 = −                + ℎ            − ℎ                     
                                              
                            2 =                 +                   −                  
                            1 =                 −                   +                   − hum                + ℎ               
                            0 = −                  +                  
                                 2
                                             2
                            4 =        −                 + ℎ            2   
                                     
                                                2  2                          2
                            3 =                 +                 − ℎ            + ℎ                    + ℎ                      −          +                  
                                                                                  
                                                     
                                                         2   2
                            2 =                 −                 −                 + ℎ            +                   +                   −                  
                                                               
                             −ℎ                      −                   + ℎ                   
                            1 = −                +                 −                   + ℎ ℎ                     −                   +                   −                    
                             − hum                +                    
                            0 =                 −                   +                   − hum                + hum               
                                         2
                            3 = −ℎ                    +          −                  
                                             
                                       2   2
                            2 =                 − ℎ            −                   +                   + ℎ                      +                  
                                             
                            1 = −                +                   +                   −                   +                     −                    
                            0 = −                +                   −                   + ℎ                    − ℎ                   
                            2 = −                  − ℎ                   
                            1 = − hum                +                     + hum                −                    
                            0 = hum                − hum               
               According to Formula (1) and (8), the transfer function from the rotation angle of steering wheel        (  ) to the
               rotation angle of front wheel   (  ) can be expressed as
                                      (  )                                          +         
                                           =                                                            (9)
                                           (  )  2             2     1           (  )    (  )    (  )
                                                 2    +    2    +    2 +  +   +    1   (  )
                                                                  2       (  )    (  )
               where
                        2
                X 2 = m            1 +    1    2                  
                           
               
               
               
               
                                               2 2
                                           2
                         2                                     
                    2 =            +    2                   +  2  2     1
                             
                                          2         1
               
               
               
                                           2       1
                   2 =                           +             1 −
                                               1
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